x^2+2x-3762=0

Solution for x^2+2x-3762=0 equation:

x^2+2x-3762=0

a = 1; b = 2; c = -3762;
Δ = b2-4ac
Δ = 22-4·1·(-3762)
Δ = 15052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15052}=\sqrt{4*3763}=\sqrt{4}*\sqrt{3763}=2\sqrt{3763}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{3763}}{2*1}=\frac{-2-2\sqrt{3763}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{3763}}{2*1}=\frac{-2+2\sqrt{3763}}{2}
$